all-project/script/sql/fix-project-application-applicant-id.sql

-- 修复项目申报表中申请人ID为空的问题
-- 日期: 2025-08-01
-- 说明: 检查并修复cw_project_application表中applicant_id和department_id为空的记录

-- 1. 查看当前有问题的记录
SELECT 
    id, 
    application_no, 
    project_name, 
    applicant_id, 
    applicant_name,
    department_id,
    department_name,
    create_by,
    approval_status
FROM cw_project_application 
WHERE applicant_id IS NULL 
   OR applicant_id = 0 
   OR department_id IS NULL 
   OR department_id = 0
ORDER BY create_time DESC;

-- 2. 修复applicant_id为空的记录（使用create_by作为申请人ID）
UPDATE cw_project_application 
SET applicant_id = create_by
WHERE (applicant_id IS NULL OR applicant_id = 0) 
  AND create_by IS NOT NULL 
  AND create_by > 0;

-- 3. 修复applicant_name为空的记录（从sys_user表获取用户名）
UPDATE cw_project_application cpa
INNER JOIN sys_user su ON cpa.applicant_id = su.user_id
SET cpa.applicant_name = su.user_name
WHERE (cpa.applicant_name IS NULL OR cpa.applicant_name = '')
  AND cpa.applicant_id IS NOT NULL;

-- 4. 修复department_id为空的记录（从sys_user表获取部门ID）
UPDATE cw_project_application cpa
INNER JOIN sys_user su ON cpa.applicant_id = su.user_id
SET cpa.department_id = su.dept_id
WHERE (cpa.department_id IS NULL OR cpa.department_id = 0)
  AND cpa.applicant_id IS NOT NULL
  AND su.dept_id IS NOT NULL;

-- 5. 修复department_name为空的记录（从sys_dept表获取部门名称）
UPDATE cw_project_application cpa
INNER JOIN sys_dept sd ON cpa.department_id = sd.dept_id
SET cpa.department_name = sd.dept_name
WHERE (cpa.department_name IS NULL OR cpa.department_name = '')
  AND cpa.department_id IS NOT NULL;

-- 6. 对于仍然无法修复的记录，设置为系统管理员（ID=1）
UPDATE cw_project_application 
SET applicant_id = 1,
    applicant_name = 'admin',
    department_id = 103,
    department_name = '研发部门'
WHERE applicant_id IS NULL 
   OR applicant_id = 0
   OR department_id IS NULL 
   OR department_id = 0;

-- 7. 验证修复结果
SELECT 
    COUNT(*) as total_records,
    COUNT(CASE WHEN applicant_id IS NULL OR applicant_id = 0 THEN 1 END) as null_applicant_id,
    COUNT(CASE WHEN department_id IS NULL OR department_id = 0 THEN 1 END) as null_department_id,
    COUNT(CASE WHEN applicant_name IS NULL OR applicant_name = '' THEN 1 END) as null_applicant_name,
    COUNT(CASE WHEN department_name IS NULL OR department_name = '' THEN 1 END) as null_department_name
FROM cw_project_application;

-- 8. 显示修复后的记录
SELECT 
    id, 
    application_no, 
    project_name, 
    applicant_id, 
    applicant_name,
    department_id,
    department_name,
    approval_status,
    create_time
FROM cw_project_application 
ORDER BY create_time DESC
LIMIT 10;