all-project/script/sql/fix-applicant-id-issue.sql

-- ==========================================
-- 修复项目申报中申请人ID为空的问题
-- 创建时间: 2025-08-01
-- 描述: 检查并修复cw_project_application表中applicant_id为NULL的记录
-- ==========================================

-- 1. 检查问题记录
SELECT 
    id,
    application_no,
    project_name,
    applicant_id,
    applicant_name,
    department_id,
    department_name,
    approval_status,
    create_by,
    create_time
FROM cw_project_application 
WHERE applicant_id IS NULL OR applicant_id = 0;

-- 2. 修复方案1：将申请人ID设置为创建者ID（推荐）
UPDATE cw_project_application 
SET 
    applicant_id = create_by,
    applicant_name = (
        SELECT nick_name 
        FROM sys_user 
        WHERE user_id = cw_project_application.create_by 
        AND deleted = 0
        LIMIT 1
    )
WHERE (applicant_id IS NULL OR applicant_id = 0) 
  AND create_by IS NOT NULL
  AND create_by > 0;

-- 3. 修复方案2：如果创建者也为空，设置为系统管理员（ID=1）
UPDATE cw_project_application 
SET 
    applicant_id = 1,
    applicant_name = '系统管理员'
WHERE (applicant_id IS NULL OR applicant_id = 0) 
  AND (create_by IS NULL OR create_by = 0);

-- 4. 修复部门信息为空的记录
UPDATE cw_project_application 
SET 
    department_id = (
        SELECT dept_id 
        FROM sys_user 
        WHERE user_id = cw_project_application.applicant_id 
        AND deleted = 0
        LIMIT 1
    ),
    department_name = (
        SELECT d.dept_name 
        FROM sys_user u 
        LEFT JOIN sys_dept d ON u.dept_id = d.dept_id 
        WHERE u.user_id = cw_project_application.applicant_id 
        AND u.deleted = 0 
        AND d.deleted = 0
        LIMIT 1
    )
WHERE (department_id IS NULL OR department_id = 0) 
  AND applicant_id IS NOT NULL 
  AND applicant_id > 0;

-- 5. 验证修复结果
SELECT 
    '修复后检查' as check_type,
    COUNT(*) as total_records,
    SUM(CASE WHEN applicant_id IS NULL OR applicant_id = 0 THEN 1 ELSE 0 END) as null_applicant_count,
    SUM(CASE WHEN department_id IS NULL OR department_id = 0 THEN 1 ELSE 0 END) as null_department_count
FROM cw_project_application;

-- 6. 显示修复后的记录
SELECT 
    id,
    application_no,
    project_name,
    applicant_id,
    applicant_name,
    department_id,
    department_name,
    approval_status
FROM cw_project_application 
ORDER BY create_time DESC 
LIMIT 10;